In a multiple choice test with 20 questions, each question has 4 choices and a student guesses on all of them. What is the probability that the student answers exactly 5 questions correctly?



Answer :

Answer:

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4

3

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15

=(

4

3

)

15

=

4

15

3

15

Step-by-step explanation:

To find the probability that the student answers exactly 5 questions correctly, we'll use the binomial probability formula:

\[ P(X = k) = \binom{n}{k} \times p^k \times (1 - p)^{n - k} \]

Where:

- \( n \) is the number of trials (number of questions),

- \( k \) is the number of successes (number of questions answered correctly),

- \( p \) is the probability of success on each trial (probability of answering a question correctly), and

- \( \binom{n}{k} \) is the binomial coefficient, which represents the number of ways to choose \( k \) successes out of \( n \) trials.

In this case:

- \( n = 20 \) (20 questions),

- \( k = 5 \) (5 questions answered correctly),

- \( p = \frac{1}{4} \) (probability of guessing a question correctly), and

- \( 1 - p = \frac{3}{4} \) (probability of guessing incorrectly).

Let's calculate:

\[ P(X = 5) = \binom{20}{5} \times \left(\frac{1}{4}\right)^5 \times \left(\frac{3}{4}\right)^{20 - 5} \]

\[ P(X = 5) = \binom{20}{5} \times \left(\frac{1}{4}\right)^5 \times \left(\frac{3}{4}\right)^{15} \]

Now, let's compute each part:

\[ \binom{20}{5} = \frac{20!}{5!(20 - 5)!} = \frac{20!}{5!15!} = \frac{20 \times 19 \times 18 \times 17 \times 16}{5 \times 4 \times 3 \times 2 \times 1} \]

\[ \left(\frac{1}{4}\right)^5 = \left(\frac{1}{4}\right)^5 = \frac{1}{4^5} = \frac{1}{1024} \]

\[ \left(\frac{3}{4}\right)^{15} = \left(\frac{3}{4}\right)^{15} = \frac{3^{15}}{4^{15}} \]

Now, let's calculate these values and multiply them together to find \( P(X = 5) \).