[tex]\huge\ \star\;{\underline{\underline{\pmb{\mathtt{Answer:}}}}}[/tex]
In Right angle triangle, ∆ABC.. [tex]\sf{\angle B = 90°}[/tex]
By Pythagorus theorem :-
Dividing both sides by AC²
- [tex]\sf{ →\frac{{AC}^{2} }{{AC}^{2} } \: = \frac{{AB}^{2} }{{AC}^{2} } + \frac{{BC}^{2} }{{AC}^{2} } }[/tex]
- [tex]\sf{ → 1 \: = (\frac{{{AB}^{2} }}{{AC}^{2} }) + (\frac{{BC}^{2} }{{AC}^{2} } ) }[/tex]
- [tex]\sf{ → 1 \: = { cos }^{2}A + { sin }^{2} A }[/tex]
