The table shows a relationship between
x and y.
X23
4
9
5 10
6 12
8 16
Does this relationship represent a
proportional linear equation?
A Yes, because there is a constant rate
of 2.
B
Yes, because the graph would
contain the point (0, 0).
C No, because the graph would
contain the point (0, 0).
D Yes, because there is a constant rate
of change of
Help pls

The table shows a relationship between x and y X23 4 9 5 10 6 12 8 16 Does this relationship represent a proportional linear equation A Yes because there is a c class=


Answer :

Answer:

A. Yes, because there is a constant rate of 2.

Step-by-step explanation:

A proportional linear equation describes a relationship between two variables where one is directly proportional to the other. In other words, as one variable changes, the other changes in direct proportion to it.

[tex]\boxed{\begin{array}{l}\underline{\textsf{Proportional linear equation}}\\\\y=kx\\\\\textsf{where:}\\\phantom{ww}\bullet\;\textsf{$y$ is the dependent variable.}\\\phantom{ww}\bullet\;\textsf{$x$ is the independent variable.}\\\phantom{ww}\bullet\;\textsf{$k$ is the constant of proportionality.}\end{array}}[/tex]

As x increases or decreases, y changes in direct proportion to x. The constant k represents the ratio between y and x, indicating how much y changes for each unit change in x.

If we substitute x = 0 into a proportional linear equation, we get y = 0, so the graph of a proportional linear equation will always contain point (0, 0).

To determine if the relationship between x and y is proportional, calculate the ratio of y to x for each row of the table. If the ratio is the same for all rows, the relationship is proportional:

[tex]\dfrac{4}{2}=2\\\\\\\dfrac{6}{3}=2\\\\\\\dfrac{10}{5}=2\\\\\\\dfrac{12}{6}=2\\\\\\\dfrac{16}{8}=2[/tex]

So, the constant of proportionality is 2, and so the equation of the relationship is y = 2x.

Therefore, the relationship is proportional because:

  • The ratios of y/x of each row of the table are the same.
  • The graph passes through the origin (0, 0).
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