Answer :

To find the center and the radius of a circle when given its equation in general form, you must first identify the equation in its standard form. The standard form of a circle's equation is typically written as: (x - h)² + (y - k)² = r² where (h, k) represents the center of the circle and r is the radius. The equation you have given seems to be in a non-standard format and could be interpreted as: 2x² + 2y² = 16 To convert this equation into standard form, we need to isolate x² and y² on the left-hand side and express the equation in terms of (x - h)² and (y - k)². Divide both sides of the equation by 2 to simplify the terms associated with x² and y²: x² + y² = 8 This equation now resembles the standard form, where: - h = 0 because there is no term subtracted from x, which implies x - 0 or simply x. - k = 0 because there is no term subtracted from y, which implies y - 0 or simply y. - r² = 8 Now we can see that the center of the circle (h, k) is (0, 0) because the equation does not have (x - h) or (y - k) but just x² and y². To find the radius r, we take the square root of r²: r = √8 To simplify the square root of 8, we can write it as: r = √(4 * 2) Since √4 is 2, we can simplify further: r = 2√2 So, the radius of the circle is 2√2. In summary, the center of the circle is (0, 0) and the radius is 2√2.