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A baseball player exerts a force of 50N on a ball for a distance of .5m as he throws it. If the ball has a mass of .25 kg what is the velocity as it leaves his hand



Answer :

MathPhys

Answer:

14.1 m/s

Explanation:

The work-energy theorem says that the work done on an object is equal to its change in kinetic energy. Work is force times distance, and kinetic energy is half the mass times the square of the speed.

W = ΔKE

Fd = ½ mv²

v² = 2Fd / m

v² = 2 (50 N) (0.5 m) / (0.25 kg)

v = 14.1 m/s

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