Answer: At t = 2 seconds: The wave has traveled half a period, so the crest will be at x = 10m. Therefore, the vertical position of the surface of the water at x = 10m at t = 2 seconds will be at its maximum height, which corresponds to the crest.
At t = 4 seconds: One complete cycle has occurred, so the wave will be at the same position as it was at t = 0 seconds. Therefore, the vertical position of the surface of the water at x = 10m at t = 4 seconds will be at its maximum height, which corresponds to the crest.
At t = 6 seconds: The wave has traveled one and a half periods, so the trough will be at x = 10m. Therefore, the vertical position of the surface of the water at x = 10m at t = 6 seconds will be at its minimum height, which corresponds to the trough.
At t = 8 seconds: Two complete cycles have occurred, so the wave will be at the same position as it was at t = 0 seconds. Therefore, the vertical position of the surface of the water at x = 10m at t = 8 seconds will be at its maximum height, which corresponds to the crest.
Explanation: