Answer :

Theliferacer1

Step-by-step explanation:

check your question it's f(x) = 12x² - 3

Given :- f(x) = 12x² - 3

  • f(x) = 12x² + 3 = 12x² - 3 / 12

  • f(x) = 12x²/12 - 3 /12
  • f(x) = x² - 1/4

  • f(x) = x² + 1/2x - 1/2x -1/4

  • f(x) = x( x + 1/2) - 1/2 ( x + 1/2)

  • f(x) = (x +1/2) (x -1/2) = 0

  • x+ 1/2 = 0 , x - 1/2 = 0

  • x = -1/2, x = 1/2 ..

Value of x = 1/2 and x = -1/2 .

MathPhys

Answer:

x = ±1/2

Step-by-step explanation:

To find the zeros of a function f(x), set f(x) = 0 and solve for x.

f(x) = 12x² − 3

Set f(x) = 0.

0 = 12x² − 3

Add 3 to both sides.

3 = 12x²

Divide both sides by 12.

3/12 = x²

1/4 = x²

Take square root of both sides.

x = ±√(1/4)

x = ±1/2

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