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A satellite is at an altitude of 9.0 × 105 m above the surface of the earth. The radius of Earth is 6.37 × 106 m and the mass is 5.97× 1024 kg. What would the acceleration due to gravity be at that height above the Earth's surface?



Answer :

MathPhys

Answer:

7.53 m/s²

Explanation:

The acceleration due to gravity is equal to the gravitational constant times the mass of the Earth divided by the square of the distance from the Earth's center.

g = GM / R²

g = (6.67×10⁻¹¹ m³/kg/s²) (5.97×10²⁴ kg) / (9.0×10⁵ m + 6.37×10⁶ m)²

g = (6.67×10⁻¹¹ m³/kg/s²) (5.97×10²⁴ kg) / (9.0×10⁵ m + 6.37×10⁶ m)²

g = 7.53 m/s²

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