The equation of a line can be represented in the slope-intercept form, which is y = mx + b, where m is the slope of the line and b is the y-intercept.
Given that the line passes through the point (3, 5) and has a slope of -1/1, we can plug in these values into the equation to find the specific equation of the line.
1. Substitute the slope (-1/1) into the equation: y = (-1/1)x + b
2. Substitute the coordinates of the point (3, 5) into the equation to solve for b:
5 = (-1/1)(3) + b
5 = -3 + b
b = 8
3. Now that we have the y-intercept (b = 8), we can write the final equation of the line:
y = -x + 8
Therefore, the equation of the line that passes through the point (3, 5) and has a slope of -1/1 is y = -x + 8.
