To calculate the moles of water produced when 0.35 moles of oxygen gas reacts with hydrogen gas, we first need to determine the limiting reactant in the reaction. This will tell us which reactant will be completely consumed and thus dictate the amount of product formed.
Given the balanced chemical equation:
2 H2 + O2 -> 2 H2O
1) Calculate the moles of water produced from 0.35 moles of oxygen gas:
- Determine the moles of hydrogen gas required to react with 0.35 moles of oxygen gas based on the stoichiometry of the balanced equation.
- Since the balanced equation shows a 1:1 ratio between oxygen gas (O2) and water (H2O), 0.35 moles of oxygen gas will react with an equal amount of hydrogen gas.
- Therefore, 0.35 moles of oxygen gas will produce 0.35 moles of water according to the stoichiometry of the reaction.
Thus, when 0.35 moles of oxygen gas reacts with hydrogen gas, it will produce 0.35 moles of water.
