A 60 kg crate is being pushed on a horizontal floor at constant velocity. Given
that the coefficient of kinetic friction between crate and floor is uk = 0.13,
what is the push force F in Newtons? Do not enter the units as part of your answer. Doing so will result in an incorrect answer.



Answer :

Answer:

Explanation:

Normal force = mg = 60 (9.81)

Friction force = normal force * coefficient of friction

                         = ( 60)(9.81)(.13)  = 76.5 N

This is the force, in Newtons required to push the crate at constant velocity:

76.5