As a box is pushed 30 m across a horizontal floor by a constant horizontal force of 25 N, the
kinetic energy
of the box increases by 300 J. How much total internal energy (work done on
the box by friction) is produced
during this process?
a.150 J
b. 450 J
c. 250 J
d.750 J



Answer :

Answer:

b. 450 J

Explanation:

Energy is conserved. The work done pushing the box is equal to the change in kinetic energy plus the work done by friction.

Fd = ΔKE + W

(25 N) (30 m) = 300 J + W

W = 450 J