Dale has $3,000 to invest. He has a goal to have $6,300 in this investment in 11 years. At what annual rate compounded continuously will Dale reach his goal?
Dale would reach his goal with an annual interest rate of %.
(Simplify your answer. Round to two decimal places as needed.)



Answer :

Answer: 6.75%

Step-by-step explanation:

To find the annual interest rate compounded continuously, we can use the formula for continuous compounding:

=

×

A=P×e

rt

Where:

A is the amount of money accumulated after n years, including interest.

P is the principal amount (the initial amount of money).

r is the annual interest rate (in decimal).

t is the time the money is invested for in years.

e is the base of the natural logarithm, approximately equal to 2.71828.

Given:

P = $3,000

A = $6,300

=

11

t=11 years

We need to solve for

r:

6300

=

3000

×

11

6300=3000×e

11r

Divide both sides by 3000:

11

=

6300

3000

e

11r

=

3000

6300

11

=

2.1

e

11r

=2.1

Now, take the natural logarithm of both sides:

11

=

ln

(

2.1

)

11r=ln(2.1)

=

ln

(

2.1

)

11

r=

11

ln(2.1)

Now, we can calculate the value of

r:

0.741937

11

0.06745

r≈

11

0.741937

≈0.06745

To express this as a percentage, we multiply by 100:

0.06745

×

100

%

6.75

%

r≈0.06745×100%≈6.75%

So, Dale would reach his goal with an annual interest rate of approximately 6.75%