Problema 2.- ¿Cuántas calorías se deben suministrar para que
su temperatura de 26°C a 140°C?
Problema 3.- Determine el calor específico de una pieza de 720.325 gramos que requiere 2300 calorias para
elevar su temperatura de 37°C a 140°C. Consulte el cuadro de
calores específicos para identificar que tipo de
sustancia se trata.
Problema 4. Se colocan 100 g de agua a 12 °C en un congelador y se obtienen cubitos de hielo a -8 °C.



Answer :

**Problema 2:** To calculate the amount of heat energy needed to raise the temperature of a substance, you can use the formula: Q = mcΔT Where: Q = heat energy m = mass of the substance c = specific heat capacity of the substance ΔT = change in temperature Given that the substance needs to go from 26°C to 140°C, the change in temperature is 140°C - 26°C = 114°C. If the specific heat capacity of the substance is known, you can calculate the heat energy required. If not, the question may need additional information. **Problema 3:** For this problem, we need to determine the specific heat capacity of the substance. The formula to calculate the specific heat capacity is: c = Q / (m * ΔT) Given that the mass (m) is 720.325 grams, the heat energy (Q) required is 2300 calories, and the change in temperature (ΔT) is from 37°C to 140°C. By substituting these values into the formula, we can calculate the specific heat capacity of the substance. Once you have the specific heat capacity value, you can refer to a table of specific heat capacities to identify the substance based on the calculated value. **Problema 4:** In this scenario, we are dealing with a phase change of water from liquid to solid (ice). To calculate the heat energy absorbed or released during a phase change, you can use the formula: Q = m * L Where: Q = heat energy m = mass of the substance L = specific latent heat of fusion for water (334 J/g) Given that we are dealing with 100 g of water turning into ice at -8°C, you need to account for the heat absorbed during the phase change. Calculate the heat energy required for the phase change from water at 12°C to ice at -8°C using the formula above. By following these steps, you can effectively solve each problem by applying the relevant formulas and concepts related to heat energy and specific heat capacity.