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a businesswoman pulls a 5.78 kg suitcase in a northern direction, with a force of 30.4 n. a hust of wind blows adding a counteracting 8.92 n force of friction eastward. n what direction does the suitcase accelerate? Theta = ? degrees



Answer :

MathPhys

Answer:

73.6° north of east

Explanation:

The direction of the suitcase can be found using trigonometry.

tan θ = Fᵧ / Fₓ

tan θ = 30.4 / 8.92

tan θ = 3.41

θ = 73.6°

The suitcase accelerates 73.6° above the +x axis or 73.6° north of east.

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