. A hocky puck of mass 0.100 kg moves along the horizontally and to the right at a speed of 5.00m/s. The puck collides (with a glancing blow) with a stationary puck (mass = 0.100kg). After the collision, the original puck moves off at an angle of 30.0 degrees to the left of the original horizontal directions at a speed of 2.00 m/s. What is the velocity of the second puck after the collision?

To find the velocity of the second puck after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision, provided there are no external forces acting on the system.

Let's denote the initial velocity of the second puck as

and the final velocity of the first puck after the collision as

.

1. Calculate the initial momentum of the system:

Given:

,

2. Calculate the final momentum of the system:

Given:

,

We need to find

.

3. Calculate the x-component of the final velocity of the first puck:

4. Calculate the y-component of the final velocity of the first puck:

5. Apply the conservation of momentum in the x-direction:

6. Solve for

to find the x-component of the final velocity of the second puck.

7. Once you have the x-component of the final velocity of the second puck, you can find the y-component using the y-component of the final velocity of the first puck.

This approach will help you calculate the velocity of the second puck after the collision by considering the conservation of momentum and the angle at which the first puck moves after the collision

Explanation: