Answer:
0
Step-by-step explanation:
It seems like you want to simplify the expression (x2)(a−b)+(x2)(b−c)+(x2)(c−a)(x2)(a−b)+(x2)(b−c)+(x2)(c−a).Let's simplify it step by step:(x2)(a−b)(x2)(a−b) can be expanded as x2a−x2bx2a−x2b.(x2)(b−c)(x2)(b−c) can be expanded as x2b−x2cx2b−x2c.(x2)(c−a)(x2)(c−a) can be expanded as x2c−x2ax2c−x2a.Now, let's combine these terms:(x2)(a−b)+(x2)(b−c)+(x2)(c−a)(x2)(a−b)+(x2)(b−c)+(x2)(c−a)
=(x2a−x2b)+(x2b−x2c)+(x2c−x2a)=(x2a−x2b)+(x2b−x2c)+(x2c−x2a)Now, let's group like terms together:=x2a−x2b+x2b−x2c+x2c−x2a=x2a−x2b+x2b−x2c+x2c−x2aNow, we can see that x2bx2b and −x2b−x2b will cancel each other out, and similarly x2cx2c and −x2c−x2c will cancel each other out.=x2a−x2a=x2a−x2aFinally, the x2ax2a and −x2a−x2a will also cancel out.=0=0So, the simplified expression is 00.
