Answer:
The given quadrilateral ABCD is cyclic quadrilateral.
So, the opposite angles B and D, and A and C are supplementary.
[tex]\therefore\ \angle\text{B}+\angle\text{D}=180\\\text{or, }2x+3x-5=180\\\text{or, }5x-5=180\\\text{or, }5x=185\\\text{or, }x=37[/tex]
[tex]\therefore\ \angle\text{A}=x+5=37+5=42[/tex]
[tex]\angle\text{B}=2x=2\times37=74\\\\\angle\text{D}=3x-5=3(37)-5=106[/tex]