Certainly! When evaluating the function h for x = 0 and x = 4, we follow the given conditions:
1. For x = 0:
- Since x < 0 is not true for x = 0, we move to the next condition.
- h(x) = 2x^2/(3x + 10)
- Substitute x = 0 into the function:
h(0) = 2(0)^2 / (3(0) + 10)
h(0) = 0 / 10
h(0) = 0
2. For x = 4:
- Since 0 < x < 4 is not true for x = 4, we move to the next condition.
- h(x) = 2x^2/(3x + 10)
- Substitute x = 4 into the function:
h(4) = 2(4)^2 / (3(4) + 10)
h(4) = 32 / (12 + 10)
h(4) = 32 / 22
h(4) = 16 / 11 (you can leave the answer in fraction form or as a decimal)
Therefore, h(0) = 0 and h(4) = 16/11 or approximately 1.45.
