8. Which is the equation of a circle that has a diameter with endpoints (1,3) and (-3,1)?
A. (x + 1)²+(y-2)² = 10
B. (x+1)²+(y-2)² = 20
C. (x+1)²+(y-2)² = 5
D. (x-1)²+(y-2)²=5



Answer :

The equation of a circle can be found when you know the endpoints of its diameter. To find the center of the circle, you take the average of the x-coordinates and the average of the y-coordinates of the endpoints of the diameter. For this case: Center = ((1-3)/2, (3+1)/2) = (-1, 2) Then, you find the radius of the circle by calculating the distance between one endpoint of the diameter and the center using the distance formula. Radius = √[(-3 - (-1))² + (1 - 2)²] = √[(-2)² + (-1)²] = √[4 + 1] = √5 Therefore, the equation of the circle with center (-1, 2) and radius √5 is: (x + 1)² + (y - 2)² = 5 So, the correct answer is: D. (x - 1)² + (y - 2)² = 5