The solutions of the equation x^2 + 8x = 20 can be found by first rearranging the equation to set it equal to zero:
x^2 + 8x - 20 = 0
To find the solutions, we can use the quadratic formula, which is given by:
x = (-b ± √(b^2 - 4ac)) / 2a
In this case, a = 1, b = 8, and c = -20. Substituting these values into the formula, we get:
x = (-8 ± √(8^2 - 4*1*(-20))) / 2*1
x = (-8 ± √(64 + 80)) / 2
x = (-8 ± √144) / 2
x = (-8 ± 12) / 2
This gives us two possible solutions:
x = (-8 + 12) / 2 = 4 / 2 = 2
x = (-8 - 12) / 2 = -20 / 2 = -10
Therefore, the correct solutions to the equation x^2 + 8x = 20 are x = 2 and x = -10.
