The air temperature above coastal areas is profoundly influenced by the
large specific heat capacity of water. How large of volume of air can be
cooled by 1.0°C if energy is transferred as heat from the air to the water,
thus increasing the temperature of 1.0 kg of water by 1.0°C? The specific
heat capacity of air is approximately 1000.0J/kg °C, and the density of
air is approximately 1.29 kg/m³.
71 Liters



Answer :

The question asks how much air can be cooled by 1.0°C if the energy is transferred from the air to water, increasing the temperature of 1.0 kg of water by 1.0°C. To calculate this, we need to consider the specific heat capacities of air and water. 1. Calculate the energy transferred from air to water using the specific heat capacities: - Specific heat capacity of air = 1000 J/kg°C - Mass of water = 1.0 kg - Change in temperature of water = 1.0°C 2. Calculate the energy transferred from air to water: Energy transferred = mass of water × specific heat capacity of water × change in temperature Energy transferred = 1.0 kg × 4186 J/kg°C × 1.0°C 3. Now, convert this energy into the amount of air that can be cooled by 1.0°C: - Density of air = 1.29 kg/m³ 4. Calculate the volume of air that can be cooled by 1.0°C: Volume of air = Energy transferred / (specific heat capacity of air × density of air) Volume of air = (1.0 kg × 4186 J/kg°C × 1.0°C) / (1000 J/kg°C × 1.29 kg/m³) 5. After performing the calculations, the result is 71 liters of air that can be cooled by 1.0°C when the energy is transferred from the air to water.