To find out how many grams of aluminum oxide are produced in the reaction, we need to follow these steps:
1. Calculate the number of moles of Al and O₂ separately using their molar masses from the periodic table.
2. Identify the limiting reactant (the reactant that will be completely consumed).
3. Use the mole ratio from the balanced chemical equation to determine the moles of aluminum oxide produced.
4. Convert the moles of aluminum oxide to grams.
Let's start with the calculations:
1. Calculate the number of moles of Al:
- Molar mass of Al = 26.98 g/mol
- Moles of Al = Mass of Al / Molar mass of Al
= 15.6 g / 26.98 g/mol
2. Calculate the number of moles of O₂:
- Molar mass of O₂ = 32.00 g/mol
- Moles of O₂ = Mass of O₂ / Molar mass of O₂
= 15.6 g / 32.00 g/mol
3. Determine the limiting reactant by comparing the moles of Al and O₂ using the coefficients from the balanced equation:
- The balanced equation shows that 4 moles of Al react with 3 moles of O₂.
- Calculate the mole ratio of Al to O₂ based on the given masses and molar masses.
4. Use the limiting reactant to find the moles of Al₂O₃ produced:
- The balanced equation states that 4 moles of Al produce 2 moles of Al₂O₃.
- Use the mole ratio to calculate the moles of Al₂O₃ produced.
5. Convert moles of Al₂O₃ to grams:
- Molar mass of Al₂O₃ = 101.96 g/mol
- Grams of Al₂O₃ = Moles of Al₂O₃ × Molar mass of Al₂O₃
By following these steps, you will be able to determine the grams of aluminum oxide produced in the reaction based on the given quantities of Al and O₂.
