Answered

Apprenti Math Assessment Question 31 of 61
Use the system of equations below to solve for z.
6w-4z+2y+8x=52
2y-4w-6x-2z=-28
6z+2x-4w+4y=36
4x+4y-2w-2z=20
Answer *
6
O4
O3
Submit
Contact Information
18°C Sunny
My Sonicrosser



Answer :

To solve for z in the system of equations given, we need to eliminate variables step by step. Let's go through the process: 1. Start by rearranging the equations to isolate z: - Equation 1: 6w - 4z + 2y + 8x = 52 Rearrange: -4z = -6w - 2y - 8x + 52 Divide by -4: z = 1.5w + 0.5y + 2x - 13 - Equation 2: 2y - 4w - 6x - 2z = -28 Rearrange: -2z = -2y + 4w + 6x - 28 Divide by -2: z = y - 2w - 3x + 14 - Equation 3: 6z + 2x - 4w + 4y = 36 Rearrange: 6z = -2x + 4w - 4y + 36 Divide by 6: z = -0.33x + 0.67w - 0.67y + 6 - Equation 4: 4x + 4y - 2w - 2z = 20 Rearrange: -2z = -4x - 4y + 2w + 20 Divide by -2: z = 2x + 2y - w - 10 2. Now, we have z expressed in terms of the other variables in each equation: - z = 1.5w + 0.5y + 2x - 13 - z = y - 2w - 3x + 14 - z = -0.33x + 0.67w - 0.67y + 6 - z = 2x + 2y - w - 10 3. Equate the expressions for z from the different equations: 1.5w + 0.5y + 2x - 13 = y - 2w - 3x + 14 Solve this equation to find the values of w, x, and y that satisfy the system and consequently find z. By following these steps, you can solve for z in the system of equations provided.