A charge of −4 × 10−9 C is a distance of 3 cm from a charge of 3 × 10−9 C . What is the magnitude and direction of the force between them?

Answer in terms of Newtons.



Answer :

Answer:

To find the magnitude of the force between the charges, we can use Coulomb's Law:

\(F = k \cdot \frac{{|q_1 \cdot q_2|}}{{r^2}}\),

where:

- \(F\) is the force,

- \(k\) is Coulomb's constant (\(8.99 \times 10^9 \, N \cdot m^2/C^2\)),

- \(q_1\) and \(q_2\) are the charges,

- \(r\) is the distance between the charges.

Plugging in the values:

\(F = (8.99 \times 10^9 \, N \cdot m^2/C^2) \cdot \frac{{|(-4 \times 10^{-9} C) \cdot (3 \times 10^{-9} C)|}}{{(0.03 \, m)^2}\).

Calculate the magnitude of the force using this formula. The direction of the force will be attractive due to the opposite signs of the charges.