Answer :
Answer: A. 3.23s
Explanation:
To calculate the time it takes for the object to travel 15.2 m, we can use the following kinematics equation:
d = v₀t + 0.5at², where:
- d is the displacement (the distance in this case)
- v₀ is the initial velocity
- t is the time
- a is the acceleration
We are given:
- d = 15.2 m
- v₀ = 0 (since the object is initially at rest)
- a = 2.9 m/s²
Let's plug these values into the formula:
15.2 = 0.5(2.9)t²
Solve for t:
15.2 = 1.45t²
15.2/1.45 = t²
t = 3.23 s
It takes 3.23 s for the object to move over 15.2 m.
To find the time it takes for an object to move over a given distance with constant acceleration, one can use the kinematic equation d = 1/2 at². Upon substituting the known values of distance (15.2 m) and acceleration (2.90 m/s²) and solving for time.hence the correct option is C. 2.29 s
To solve for the time it takes for an object initially at rest to move over a distance of 15.2 meters with a constant acceleration of 2.90 m/s², we can use the kinematic equation that relates distance (d), initial velocity (vi), acceleration (a), and time (t):
d = vit + 1/2 at²
Since the initial velocity is zero (vi = 0, as the object starts from rest), the equation simplifies to:
d = 1/2 at²
We are given:
Acceleration, a = 2.90 m/s²
Distance, d = 15.2 m
Plugging in the given values:
15.2 m = 1/2 (2.90 m/s²) t²
Solving for t² gives:
t² = (15.2 m) / (1.45 m/s²)
t² ≈ 10.48276 s²
Now, take the square root to find t:
t ≈ √10.48276 s²
t ≈ 3.23 s
Thus, the correct answer is A. 3.23 seconds.hence the correct option is C. 2.29 s
