olve the following problem. (Show your solution on a separate sheet)
1. Consider a 3.5-kg cart loaded with three 0.5-kg brick and moving with a speed of 2.0 m/s.
What is its momentum?
2. A skateboard is rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg m/s. What is its
mass?
3. A pitcher throws a baseball with a mass of 0.5 kg and a momentum of 10 kg m/s. What is its
velocity?



Answer :

To find the momentum of the cart in the first problem, you need to calculate the total momentum by adding the individual momenta of the cart and the bricks. 1. Momentum of the cart: Momentum = mass * velocity Momentum = 3.5 kg * 2.0 m/s Momentum = 7.0 kg m/s Momentum of the three bricks: Momentum = 3 * (0.5 kg * 2.0 m/s) (since each brick has the same mass and velocity) Momentum = 3 * 1.0 kg m/s Momentum = 3.0 kg m/s Total momentum = Momentum of the cart + Momentum of the bricks Total momentum = 7.0 kg m/s + 3.0 kg m/s Total momentum = 10.0 kg m/s Therefore, the total momentum of the cart with the bricks is 10.0 kg m/s. Moving on to the second problem, you are given the momentum and velocity of the skateboard and asked to find its mass. 2. Given momentum = 6.0 kg m/s Velocity = 3.0 m/s Momentum = mass * velocity 6.0 kg m/s = mass * 3.0 m/s mass = 6.0 kg m/s / 3.0 m/s mass = 2.0 kg Therefore, the mass of the skateboard is 2.0 kg. Finally, in the third problem, you have the mass and momentum of the baseball and need to calculate its velocity. 3. Given mass = 0.5 kg Momentum = 10 kg m/s Momentum = mass * velocity 10 kg m/s = 0.5 kg * velocity velocity = 10 kg m/s / 0.5 kg velocity = 20 m/s Therefore, the velocity of the baseball is 20 m/s.