3. What is the distance between (2,-1) and
(-3, 5) on the coordinate plane? Round
to the nearest tenth.
3.3 units
4.1 units
7.8 units
D 8.5 units



Answer :

Answer:

d ≈ 7.8 units

Step-by-step explanation:

calculate the distance , d , using the distance formula

• d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

let (x₁, y₁ ) = (2, - 1 ) and (x₂, y₂ ) = (- 3, 5 )

substitute these values into the formula for d

d = [tex]\sqrt{(-3-2)^2+(5-(-1))^2}[/tex]

   = [tex]\sqrt{(-5)^2+(5+1)^2}[/tex]

   = [tex]\sqrt{25+6^2}[/tex]

   = [tex]\sqrt{25+36}[/tex]

   = [tex]\sqrt{61}[/tex]

   ≈ 7.8 units ( to the nearest tenth )