Answer :
Answer:
Explanation:
I think what you meant to ask is what is the pOH and give two significant figures.
So to find the pOH given the OH- concentration, you use the formula
-log[OH-] = pOH
So by applying the formula, you get
-log(3.6*10^-11) = 10.44
So two signficant figures so the answer is 10.
If the question is what is the pH given the [OH-], well first you find the pOH then you do 14-pOH = pH so pH is 14-10.44 = 9.66, so 2 s.f. is 9.7.
Another way to find this is to divide [OH-] by 1*10^-14, which is the water dissociation constant, which gives the [H+], and use the formula -log[H+] = pH to find the pH
Hope that answers your question, whatever it was.
