Answer :

Answer:

y = -10/3

Step-by-step explanation:

So the function f(x) is composed of two other functions,

12/x - 2 and -4x-14

Now each of these functions have their respective domains where x can also be within those values.

Our given x is -9, now using this value, where can I apply this?

Well, our second equation only has x values that are more than 3, so x = -9 cannot be used there, whereas our first function has a domain where all x values are less than or equal to 3. Since -9 is less than 3, thats perfect! We can use this function

Therefore

lets plug in x = -9 to 12/x - 2

12/-9 -2 = 4/-3 - 2 =-10/3

Hope that answers your question

Answer:

f(- 9) = - [tex]\frac{10}{3}[/tex]

Step-by-step explanation:

To evaluate the function at x = - 9, in the interval x ≤ 3

Then using

f(x) = [tex]\frac{12}{x}[/tex] - 2 , substitute x = - 9

f(- 9) = [tex]\frac{12}{-9}[/tex] - 2

         = - [tex]\frac{4}{3}[/tex] - 2

        = - [tex]\frac{4}{3}[/tex] - [tex]\frac{6}{3}[/tex]

       = - [tex]\frac{10}{3}[/tex]

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