Answer :

To find all exact solutions to the equation csc^2(x) - 3 = -1 on the interval 0 ≤ x < 2, we can follow these steps: 1. Start by isolating the csc^2(x) term by adding 3 to both sides of the equation: csc^2(x) = -1 + 3 csc^2(x) = 2 2. Next, recall that csc(x) is the reciprocal of sin(x). Therefore, csc^2(x) = 1/sin^2(x). 3. Substitute csc^2(x) = 2 with 1/sin^2(x) = 2: 1/sin^2(x) = 2 1 = 2sin^2(x) sin^2(x) = 1/2 4. Take the square root of both sides to solve for sin(x): sin(x) = ±√(1/2) sin(x) = ±1/√2 sin(x) = ±√2/2 5. Since we are looking for solutions on the interval 0 ≤ x < 2, we need to find the reference angles in the first quadrant where sin(x) is positive. 6. The reference angle where sin(x) is positive and equal to √2/2 is π/4 radians (45 degrees). 7. Therefore, the solutions in the interval 0 ≤ x < 2 are: x = π/4, 3π/4 These are the exact solutions for the given equation csc^2(x) - 3 = -1 on the interval 0 ≤ x < 2.