Answer:
1.688g of I2
Explanation:
So first step before everything is to balance the equation
NI3 -> N2 + I2
Product:
N 2
I 2x3 = 6
Reactant:
N 1 x2 = 2
I 3 -> 6
2NI3 -> N2 + 3I2
So the question on whether it is decomposing or not doesn't matter. its more like if we initially have 1.75g of NI3, how much I2 made.
It can be calculated by simple stoichiometry
1.75g NI3 x (1mol NI3/394.719 g/mol NI3) x (3 mol I2/2 mol NI3) x (253.8089 g I2/mol I2)
1.688g of I2
Hope that answers your question