Para resolver este problema, podemos utilizar las ecuaciones de movimiento para objetos bajo la influencia de la gravedad.
La altura máxima (h) se alcanza cuando la velocidad (v) es cero. Podemos usar la ecuación:
v^2 = v0^2 + 2as
Donde:
v0 = velocidad inicial
a = aceleración (en este caso, la gravedad, g = -9.8 m/s^2)
s = altura máxima (h = 20 m)
Rearranging the equation to solve for v0, we get:
v0 = sqrt(2as)
= sqrt(2 * (-9.8 m/s^2) * (20 m))
= sqrt(392 m^2/s^2)
= 19.8 m/s
So, the initial velocity (v0) is approximately 19.8 m/s.
To find the time the object is in the air, we can use the equation:
t = 2v0/g
Where t is the time and g is the acceleration due to gravity (approximately 9.8 m/s^2).
Plugging in the value of v0, we get:
t = 2 * (19.8 m/s) / (9.8 m/s^2)
= 4 seconds
Therefore, the object will be in the air for approximately 4 seconds.
I am still improving my command of non-English languages, and I may make errors while attempting them. I will be most useful to you if I can assist you in English.
