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From his home, Dylan would have to walk 7 kilometers north to get to his friend Rob's house and 5.5 kilometers east to get to his friend Gwen's house. One day, Dylan walked from his home to Gwen's house. Together, Gwen and Dylan cut directly through the field that separated them from Rob's house. When they finished playing at Rob's, Dylan walked back home. In all, how far did Dylan walk? If necessary, round to the nearest tenth.



Answer :

Answer:Dylan walked a total distance of approximately 20.9 kilometers.

Explanation:Distance from Dylan's home to Gwen's house (east): 5.5 kilometers

Distance from Dylan's home to Rob's house (north): 7 kilometers

Using the Pythagorean theorem:

=

2

+

2

c=

a

2

+b

2

​

, where

=

5.5

a=5.5 kilometers and

=

7

b=7 kilometers

=

5.

5

2

+

7

2

c=

5.5

2

+7

2

​

=

30.25

+

49

c=

30.25+49

​

=

79.25

c=

79.25

​

≈

8.9

c≈8.9 kilometers (rounded to the nearest tenth)

So, the total distance Dylan walked to get to Rob's house from Gwen's house is approximately 8.9 kilometers. Then, to find the total distance Dylan walked back home, we add the distance from Gwen's house to Dylan's home:

Total distance = Distance from Dylan's home to Gwen's house + Distance from Gwen's house to Rob's house + Distance from Rob's house back to Dylan's home

Total distance = 5.5 kilometers (to Gwen's house) + 8.9 kilometers (to Rob's house) + 5.5 kilometers (back home)

Total distance = 20.9 kilometers

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