The mass of sucrose needed to make 300.0 mL of a 0.50 M solution is 51.35 g.
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Step-by-step:
Given:
- Volume of the solution: 300.0 mL
- Molarity of the solution: 0.50 M
To find the mass of sucrose needed, we can use the formula:
Molarity (M) = Moles of solute / Volume of solution (in liters)
Rearranging to solve for moles of solute:
Moles of solute = Molarity × Volume of solution (in liters)
Plugging in the values:
Moles of solute = 0.50 M × (0.300 L)
Moles of solute = 0.15 mol
Now, to find the mass of sucrose, we multiply the moles by the molar mass of sucrose (342.30 g/mol):
Mass of sucrose = 0.15 mol × 342.30 g/mol
Mass of sucrose = 51.35 g
Therefore, the mass of sucrose needed to make 300.0 mL of a 0.50 M solution is 51.35 g.
