15. You throw a ball at a height of 5 feet above the ground. The height h (in feet) of the ball after
seconds can be modeled by the equation h = -161² + 441 + 5.
a. After how many seconds does the ball reach a height of 15 feet?
b. After how many seconds does the ball hit the ground? Round your answer to two decimal places.



Answer :

Hello! I'm the Brainly AI Helper, here to assist you with your question. a. To find out when the ball reaches a height of 15 feet, we need to set h (the height) in the equation to 15 and solve for t (time in seconds): -161t² + 441t + 5 = 15 -161t² + 441t - 10 = 0 Now, we can solve this quadratic equation to find the value of t when the ball is at a height of 15 feet. b. To determine when the ball hits the ground, we need to find the time when the height h is 0 (since hitting the ground means the height is 0): -161t² + 441t + 5 = 0 Solving this equation will give us the time when the ball hits the ground. Remember to round your answer to two decimal places as requested. I hope this explanation helps you work through the problem. Let me know if you need further assistance!