Answered

7. Write the formula for the dissolution of aluminum perchlorate in water.
How many TOTAL ions (aluminum cations + perchlorate anions) would be produced as aqueous species in the water solvent if four
molecules of aluminum perchlorate dissolved? The answer is, total ions (Please enter your answer as a whole number.)
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Answer :

To write the formula for the dissolution of aluminum perchlorate in water, we first need to know the chemical formula of aluminum perchlorate, which is Al(ClO4)3. When aluminum perchlorate dissolves in water, it dissociates into its constituent ions, aluminum cations (Al^3+) and perchlorate anions (ClO4^-). The formula for the dissolution of aluminum perchlorate in water is: Al(ClO4)3 (s) → Al^3+ (aq) + 3ClO4^- (aq) For each molecule of aluminum perchlorate that dissolves, it produces one aluminum cation (Al^3+) and three perchlorate anions (ClO4^-) in aqueous solution. Therefore, if four molecules of aluminum perchlorate dissolve, the total number of ions produced would be calculated as follows: 1 Al^3+ ion per molecule × 4 molecules = 4 Al^3+ ions 3 ClO4^- ions per molecule × 4 molecules = 12 ClO4^- ions Total ions produced = 4 Al^3+ ions + 12 ClO4^- ions = 16 ions in total Thus, if four molecules of aluminum perchlorate dissolve in water, a total of 16 ions (4 aluminum cations + 12 perchlorate anions) would be produced as aqueous species in the water solvent.