23. Three boys shared some money. The youngest got 1/12 of it, the next got 1/9 and the
eldest got the remainder.
a) What fraction of the money did the eldest receive?
(6mks)



Answer :

In this scenario, three boys shared some money where the youngest received 1/12 of it, the next received 1/9, and the eldest got the remainder. To find out what fraction of the money the eldest received, we first need to determine the fractions received by the youngest and the next boy. 1. The youngest received 1/12 of the money. 2. The next boy received 1/9 of the money. To calculate the fraction of the money left for the eldest, we add the fractions received by the youngest and the next boy to get the total fraction used: 1/12 (youngest) + 1/9 (next boy) = 3/36 + 4/36 = 7/36 Since the three boys shared all the money, the fraction the eldest received is the remaining amount after what the youngest and the next boy received. This can be calculated by subtracting the total fraction used by the two boys from 1 (whole amount): 1 - 7/36 = 36/36 - 7/36 = 29/36 Therefore, the eldest boy received 29/36 of the money that was shared among the three boys.

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