Answer:
To find the equation of the line that passes through the point (-3, 4) and is parallel to the line y = x + 1, we can use the point-slope form of a linear equation:
y - y₁ = m(x - x₁)
where (x₁, y₁) is a point on the line and m is the slope of the line.
Given information:
Point on the line: (-3, 4)
Parallel to the line: y = x + 1
Step 1: Find the slope of the line y = x + 1.
The line y = x + 1 is in slope-intercept form (y = mx + b), where m is the slope, and b is the y-intercept.
Slope (m) = 1
Step 2: Use the point-slope form to write the equation of the line.
y - y₁ = m(x - x₁)
y - 4 = 1(x - (-3))
y - 4 = 1(x + 3)
Step 3: Simplify the equation.
y - 4 = x + 3
y = x + 7
Therefore, the equation of the line that passes through the point (-3, 4) and is parallel to the line y = x + 1 is y = x + 7.
