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Evaluate ∬Dx2ydA, where D is the top half of the disk with center the origin and radius 5 .
Solution: Need to use polar coordinates (if you want the integration bounds for D to be all constants) ∬Dx2ydA=∫ab∫cdrpcosq(t)sin(t)dtdr where
a=
p=
q=
c=
d=
After integration, you get the integral value (input a most simplified fraction)



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