Answer :
Balanced dissociation equation for solid lead(II) sulfate in aqueous solution:
1. Lead(II) sulfate, when dissolved in water, dissociates into its ions:
PbSO4(s) → Pb^2+(aq) + SO4^2-(aq)
2. The balanced dissociation equation shows that solid lead(II) sulfate breaks apart into lead ions (Pb^2+) and sulfate ions (SO4^2-) when it is in contact with water.
3. The (s) denotes that lead(II) sulfate is in a solid state initially, and (aq) represents the ions present in the aqueous solution after dissociation.
4. Understanding dissociation equations is crucial in chemistry to grasp how compounds break down into their respective ions when dissolved in water.
Remember, in this dissociation equation, lead(II) sulfate separates into lead ions and sulfate ions when it dissolves in water.