Q is the center of the circle.
If the area of the minor sector (smaller sector) bounded by radii LQ and MQ, and
minor arc LM, is 350m2. If the length of LQ is 18. 3m, what is
μ(ZLQM) (central angle that subtends minor arc LM)?
P


Pls explain in steps thank you



Answer :

Answer:

  about 0.4784 radians, or 27.4°

Step-by-step explanation:

You want the central angle of a sector that has an area of 350 m² and an arc length of 18.3 m.

Formulas

The formula for arc length is ...

  s = rθ

The formula for area of a sector is ...

  A = 1/2·r²θ

These tell us we can find the central angle θ from ...

  [tex]\theta=\dfrac{s^2}{2A}=\dfrac{(r\theta)^2}{2(\dfrac{1}{2}r^2\theta)}=\dfrac{r^2\theta^2}{r^2\theta}[/tex]

Application

Using the given values, we find the angle (in radians) to be ...

  [tex]\theta=\dfrac{18.3^2}{2(350)}\approx\boxed{0.4784\text{ radians}\approx27.4^\circ}[/tex]

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Additional comment

We can find the radius of the circle from s/θ = r ≈ 18.3/0.4784 ≈ 38.25 m.

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