How much thermal energy does it take to raise the temperature of 2 kg water from 10°C to 26°C? The specific
heat capacity of water is 4.18 kJ/(kg °C).



Answer :

To find out how much thermal energy is required to raise the temperature of a substance, you can use the formula: \[ Q = mc\Delta T \] where: - \( Q \) is the thermal energy in joules (J) or kilojoules (kJ) - \( m \) is the mass of the substance in kilograms (kg) - \( c \) is the specific heat capacity in J/(kg·°C) or kJ/(kg·°C) - \( \Delta T \) is the change in temperature in degrees Celsius (°C) In this case, you want to raise the temperature of water, which has a specific heat capacity \( c = 4.18 \) kJ/(kg·°C), from 10°C to 26°C. The mass of the water is 2 kg. First, calculate the change in temperature: \[ \Delta T = T_{final} - T_{initial} = 26°C - 10°C = 16°C \] Now we can plug the values we have into the formula: \[ Q = mc\Delta T = 2 \, \text{kg} \times 4.18 \, \text{kJ/(kg·°C)} \times 16°C \] \[ Q = 2 \times 4.18 \times 16 \] \[ Q = 8.36 \times 16 \] \[ Q = 133.76 \, \text{kJ} \] So it takes 133.76 kJ of thermal energy to raise the temperature of 2 kg of water from 10°C to 26°C.