(b). A travelling wave travels with a velocity of 20 ms-1, and the distance from a crest to the nearest trough is
20m. Determine the period of such a wave.



Answer :

To determine the period of the wave, let's follow a step-by-step approach using the given information: Step 1: Understand the given quantities - Wave velocity (v) = 20 meters per second (ms^-1) - Distance from a crest to the nearest trough (which is half the wavelength) = 20 meters (m) Step 2: Determine the wavelength We know that a complete wave cycle includes a crest and a trough. Therefore, the distance from a crest to the nearest trough represents half a wavelength. So, to find the full wavelength (λ), we need to double this distance. Wavelength (λ) = 2 × Distance from crest to trough Wavelength (λ) = 2 × 20 m Wavelength (λ) = 40 m Step 3: Calculate the period of the wave The relationship between wave velocity (v), wavelength (λ), and period (T) is given by the formula: \[ v = \frac{λ}{T} \] This can be rearranged to solve for the period (T): \[ T = \frac{λ}{v} \] Step 4: Plug in the values and calculate the period Using the values for wavelength and wave velocity: \[ T = \frac{40 \text{ m}}{20 \text{ ms}^{-1}} \] \[ T = \frac{40}{20} \] \[ T = 2 \text{ seconds} \] So, the period of the wave is 2 seconds.