Answer :
Answer:
x=3
To solve a two-step equation that equals 9, we need to perform two operations to isolate the variable on one side of the equation.
Let's denote the variable as \(x\).
1. **Addition and Subtraction:**
An equation in the form \(ax + b = c\) or \(ax - b = c\) can be solved using addition or subtraction.
Examples:
- \(3x + 6 = 9\)
- \(5x - 3 = 9\)
To solve these equations, we'll perform the following steps:
- First, subtract or add the constant term to both sides of the equation to isolate the variable term.
- Then, divide both sides by the coefficient of the variable to solve for \(x\).
2. **Multiplication and Division:**
An equation in the form \(ax \times b = c\) or \(ax \div b = c\) can be solved using multiplication or division.
Examples:
- \(2x \times 4 = 9\)
- \(6x \div 2 = 9\)
To solve these equations, we'll perform the following steps:
- First, multiply or divide both sides of the equation to isolate the variable term.
- Then, divide both sides by the coefficient of the variable to solve for \(x\).
Let's solve one example from each category:
**Addition and Subtraction:**
\[3x + 6 = 9\]
Subtract 6 from both sides:
\[3x = 9 - 6\]
\[3x = 3\]
Divide both sides by 3:
\[x = \frac{3}{3}\]
\[x = 1\]
**Multiplication and Division:**
\[6x \div 2 = 9\]
Multiply both sides by 2:
\[6x = 9 \times 2\]
\[6x = 18\]
Divide both sides by 6:
\[x = \frac{18}{6}\]
\[x = 3\]
So, the solutions to the equations \(3x + 6 = 9\) and \(6x \div 2 = 9\) are \(x = 1\) and \(x = 3\), respectively.
