Answer :

Answer:

[tex]\bf 467[/tex]

Step-by-step explanation:

To begin, split the initial number in the dividend — 3 — by the divisor, 8. However, as 3 is less than 8, we take the first pair of digits from the dividend 37

37 divided by 8 results in 4; inscribe this outcome (4) above the division bracket.

In the first case, multiply 4 by 8, giving us 32, and subtract this value from 37 — we have 5.

Next, let's consider the next digit of the dividend (which is 3) along with our remainder: now we have 53.

By dividing 53 by 8, we get a quotient of 6 and a remainder of 5; place this quotient above the bracket with the previous one.

Our final answer is 467 without any remainder. Thus each school should receive a total of 467 yearbooks.

________________________________________________________

[tex] \bf Total \ number\ of \ yearbooks \ \div Number \ of \ schools \ = \ Year \ books \ per \ school [/tex]

[tex]\bf 3,736 \div 8 = 467[/tex]