[tex] \Large{\boxed{\sf Option \ C) \ pOH = 3.3}} [/tex]
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The pH and pOH of a solution are related to each other by the following relationship:
[tex] \Large{\left[ \begin{array}{c c c} ~ \\ \tt pH + pOH = 14 \\ ~ \end{array} \right] } [/tex]
[tex] \\ [/tex]
Given that the pH of the solution is 10.7, we can find the pOH using the above relationship.
[tex] \\ [/tex]
Substituting the given pH value into the equation:
[tex] \sf 10.7 + pOH = 14 \\ \\ \sf pOH = 14 - 10.7 \\ \\ \rightarrow \boxed{\sf pOH = 3.3} [/tex]
