Answer :

To demonstrate the formation of ionic compounds using electron-dot notation for the combinations of Li and Cl, as well as Ca and I, follow these steps: a. Formation of LiCl (Lithium Chloride): - Lithium (Li) has 1 valence electron, which is represented as •Li•. - Chlorine (Cl) has 7 valence electrons, which are represented as •Cl:•. - Lithium can donate its electron to chlorine to achieve stability. - The transfer results in Li+ (loses 1 electron) and Cl- (gains 1 electron). - The ionic compound formed is LiCl (Lithium Chloride), with Li+ and Cl- ions attracted to each other due to opposite charges. b. Formation of CaI2 (Calcium Iodide): - Calcium (Ca) has 2 valence electrons, which are represented as •Ca••. - Iodine (I) has 7 valence electrons, which are represented as •I:•. - Calcium can donate its electrons to iodine to achieve stability. - The transfer results in Ca2+ (loses 2 electrons) and I- (gains 1 electron). - Two iodine atoms are needed to accept the two electrons from calcium. - The ionic compound formed is CaI2 (Calcium Iodide), with Ca2+ and 2I- ions attracted to each other due to opposite charges. By following these steps and representing the electron transfers using electron-dot notation, you can visualize how ionic compounds are formed between elements like Li and Cl, as well as Ca and I.