Answer :

Answer:

Explanation:

You start by writing down the balanced reaction:

N

2

+ 3 H

2

→ 2 NH

3

Now, determine the numbers of moles of each component

10

g

H

2

2

g

/

m

o

l

H

2

= 5 mol H

2

30

g

N

2

28

g

/

m

o

l

N

2

= 1.0714 mol N

2

The limiting reagent is the N

2

since 1.071 mol N

2

needs 3

×

1.0714 mol = 3.2142 mole of H

2

, we have plenty of H

2

.

Since N

2

is limiting, 1.0714 mol of N

2

will make 2

×

1.0714 mol = 2.1428 mole of NH

3

.