Answer :
Answer:
Explanation:
You start by writing down the balanced reaction:
N
2
+ 3 H
2
→ 2 NH
3
Now, determine the numbers of moles of each component
10
g
H
2
2
g
/
m
o
l
H
2
= 5 mol H
2
30
g
N
2
28
g
/
m
o
l
N
2
= 1.0714 mol N
2
The limiting reagent is the N
2
since 1.071 mol N
2
needs 3
×
1.0714 mol = 3.2142 mole of H
2
, we have plenty of H
2
.
Since N
2
is limiting, 1.0714 mol of N
2
will make 2
×
1.0714 mol = 2.1428 mole of NH
3
.
