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If the legs of an isosceles right triangle have a length of 15√√2 ft, what is the length of the hypotenuse?
7.5 feet
15√2 feet
15√√3 feet
O 30 feet
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Answer :

To find the length of the hypotenuse of an isosceles right triangle, we can use the Pythagorean theorem, which is stated as a^2 + b^2 = c^2 for a triangle with sides of lengths a, b, and c, where c is the length of the hypotenuse. For an isosceles right triangle, the lengths of the two legs (sides a and b) are equal. Since we are given that each leg of the triangle has a length of \(15\sqrt{2}\) ft, we can let a = b = \(15\sqrt{2}\) ft. Now, we substitute these values into the Pythagorean theorem to find the length of the hypotenuse (c): \((15\sqrt{2})^2 + (15\sqrt{2})^2 = c^2\) Squaring \(15\sqrt{2}\) gives us: \((15\sqrt{2})^2 = 15^2 \times (\sqrt{2})^2 = 225 \times 2 = 450\) Therefore, we have: \(450 + 450 = c^2\) Adding these together gives us: \(900 = c^2\) We take the square root of both sides of the equation to find the value of c: \(\sqrt{900} = c\) The square root of 900 is 30, so: \(c = 30\) Hence, the length of the hypotenuse of an isosceles right triangle with legs of \(15\sqrt{2}\) ft each is 30 feet. The correct answer from the multiple choices given is 30 feet.